Which of the following is a solution to the given equation?
$\cot x + 1 = 0$
A) $x = \frac { 2 \pi } { 3 }$
B) $x = \frac { \pi } { 4 }$
C) $x = \frac { \pi } { 6 }$
D) $x = \frac { 7 \pi } { 4 }$
E) $x = \frac { 7 \pi } { 6 }$

Question

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The Answer of Which of the following is a solution to the given equation?
$\cot x + 1 = 0$
A) $x = \frac { 2 \pi } { 3 }$
B) $x = \frac { \pi } { 4 }$
C) $x = \frac { \pi } { 6 }$
D) $x = \frac { 7 \pi } { 4 }$
E) $x = \frac { 7 \pi } { 6 }$

Which of the Following Is a Solution to the Given cot⁡x+1=0\cot x + 1 = 0cotx+1=0

Which of the Following Is a Solution to the Given $\cot x + 1 = 0$