Solve the logarithmic equation below algebraically.
$\ln ( x + 3 ) = \ln ( x + 1 ) - \ln ( x + 7 )$
A) $1$ and $6$
B) $- 5$ and $- 4$
C) $- 4$ and $1$
D) $- 4$ and $6$
E) $- 5$ and $1$

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The Answer of Solve the logarithmic equation below algebraically.
$\ln ( x + 3 ) = \ln ( x + 1 ) - \ln ( x + 7 )$
A) $1$ and $6$
B) $- 5$ and $- 4$
C) $- 4$ and $1$
D) $- 4$ and $6$
E) $- 5$ and $1$

Solve the Logarithmic Equation Below Algebraically ln⁡(x+3)=ln⁡(x+1)−ln⁡(x+7)\ln ( x + 3 ) = \ln ( x + 1 ) - \ln ( x + 7 )ln(x+3)=ln(x+1)−ln(x+7)

Solve the Logarithmic Equation Below Algebraically $\ln ( x + 3 ) = \ln ( x + 1 ) - \ln ( x + 7 )$