Use long division to divide.
$$\left( x ^ { 3 } + 27 \right) \div ( x + 3 )$$
A) $x ^ { 2 } - 3 x + 9$
B) $x ^ { 2 } - 9$
C) $x ^ { 2 } + 3 x - 9$
D) $x ^ { 2 } + 9$
E) $x ^ { 2 } - 9 + \frac { 3 } { x + 3 }$

Question

Quizplus · Accepted Answer

The polynomial $x^3 + 27$ can be factored using the sum of cubes formula, $a^3 + b^3 = (a + b)(a^2 - ab + b^2)$, where $a = x$ and $b = 3$. This gives $(x + 3)(x^2 - 3x + 9)$. Dividing by $x + 3$ leaves $x^2 - 3x + 9$.

Use Long Division to Divide (x3+27)÷(x+3)\left( x ^ { 3 } + 27 \right) \div ( x + 3 )(x3+27)÷(x+3)

Use Long Division to Divide $\left( x ^ { 3 } + 27 \right) \div ( x + 3 )$