Graph $f ( x ) = \left\{ \begin{array} { l c } 3 x + 2 & x

Question

Graph $f ( x ) = \left\{ \begin{array} { l c } 3 x + 2 & x < - 3 \ x - 4 & x \geq - 3 \end{array} \right.$ and find the limit of $f ( x )$ as $x$ approaches $- 3$

A) $- 35$ 
B) $- 7$ 
C) $- 28$ 
D) 7 
E) limit does not exist

Quizplus · Accepted Answer

The Answer of Graph $f ( x ) = \left\{ \begin{array} { l c } 3 x + 2 & x < - 3 \ x - 4 & x \geq - 3 \end{array} \right.$ and find the limit of $f ( x )$ as $x$ approaches $- 3$

A) $- 35$ 
B) $- 7$ 
C) $- 28$ 
D) 7 
E) limit does not exist

Graph f(x)={3x+2x<−3x−4x≥−3f ( x ) = \left\{ \begin{array} { l c } 3 x + 2 & x < - 3 \\ x - 4 & x \geq - 3 \end{array} \right.f(x)={3x+2x−4​x<−3x≥−3​

Graph $f ( x ) = \left\{ \begin{array} { l c } 3 x + 2 & x < - 3 \\ x - 4 & x \geq - 3 \end{array} \right.$