Find the following limit. Round your answer to two decimals.
$$\lim _ { x \rightarrow 3 } \frac { \sqrt { x ^ { 2 } + 7 } } { 2 x ^ { 2 } }$$
A) $0.22$
B) $1.32$
C) $0.44$
D) $0.18$
E) $1.41$

Question

Quizplus · Accepted Answer

To find the limit as $x$ approaches 3, substitute $x = 3$ directly into the expression because it does not result in an indeterminate form. Thus, $\frac{\sqrt{3^2 + 7}}{2 \cdot 3^2} = \frac{\sqrt{9 + 7}}{2 \cdot 9} = \frac{\sqrt{16}}{18} = \frac{4}{18} = \frac{2}{9} \approx 0.22$.

Find the Following Limit lim⁡x→3x2+72x2\lim _ { x \rightarrow 3 } \frac { \sqrt { x ^ { 2 } + 7 } } { 2 x ^ { 2 } }x→3lim​2x2x2+7​​

Find the Following Limit $\lim _ { x \rightarrow 3 } \frac { \sqrt { x ^ { 2 } + 7 } } { 2 x ^ { 2 } }$