Use mathematical induction to prove the following for every positive integer $n$.
$$\sum _ { i = 1 } ^ { n } 36 i ^ { 5 } = 3 n ^ { 2 } ( n + 1 ) ^ { 2 } \left( 2 n ^ { 2 } + 2 n - 1 \right)$$

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The Answer of Use mathematical induction to prove the following for every positive integer $n$.
$$\sum _ { i = 1 } ^ { n } 36 i ^ { 5 } = 3 n ^ { 2 } ( n + 1 ) ^ { 2 } \left( 2 n ^ { 2 } + 2 n - 1 \right)$$

Use Mathematical Induction to Prove the Following for Every Positive nnn

Use Mathematical Induction to Prove the Following for Every Positive $n$