Solve for $x$ given the following equation involving a determinant.
$$\left| \begin{array} { c c }
x + 2 & 5 \
- 1 & x + 8
\end{array} \right| = 0$$
A) $x = 7,3$
B) $x = - 8 , - 2$
C) $x = 8,2$
D) $x = - 7 , - 3$
E) $x = 6 , - 5$

Question

Solve for $x$ given the following equation involving a determinant.
$$\left| \begin{array} { c c } 
x + 2 & 5 \
- 1 & x + 8
\end{array} \right| = 0$$
A) $x = 7,3$
B) $x = - 8 , - 2$
C) $x = 8,2$
D) $x = - 7 , - 3$
E) $x = 6 , - 5$

Quizplus · Accepted Answer

The Answer of Solve for $x$ given the following equation involving a determinant.
$$\left| \begin{array} { c c } 
x + 2 & 5 \
- 1 & x + 8
\end{array} \right| = 0$$
A) $x = 7,3$
B) $x = - 8 , - 2$
C) $x = 8,2$
D) $x = - 7 , - 3$
E) $x = 6 , - 5$

Solve For xxx Given the Following Equation Involving a Determinant ∣x+25−1x+8∣=0\left| \begin{array} { c c } x + 2 & 5 \\- 1 & x + 8\end{array} \right| = 0​x+2−1​5x+8​​=0

Solve For $x$ Given the Following Equation Involving a Determinant $\left| \begin{array} { c c } x + 2 & 5 \\- 1 & x + 8\end{array} \right| = 0$