Solve the equation below algebraically.
$$- 2 x ^ { 2 } e ^ { 4 x } - 16 x e ^ { 4 x } = 0$$
A) $- 8$ and 4
B) 4 and 5
C) $- 8$ and 5
D) 0 and 5
E) $- 8$ and 0

Name: Solve the equation below algebraically. \[- 2 x ^ { 2 } e ^ { 4 x } - 16 x e ^ { 4 x } = 0\] A) $- 8$ and 4 B) 4 and 5 C) $- 8$ and 5 D) 0 and 5 E) $- 8$ and 0
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Question

Quizplus · Accepted Answer

First, factor out the common term, which is $-2xe^{4x}$, giving $-2xe^{4x}(x + 8) = 0$. Setting each factor equal to zero gives the solutions $x = 0$ and $x = -8$.

Solve the Equation Below Algebraically −2x2e4x−16xe4x=0- 2 x ^ { 2 } e ^ { 4 x } - 16 x e ^ { 4 x } = 0−2x2e4x−16xe4x=0

Solve the Equation Below Algebraically $- 2 x ^ { 2 } e ^ { 4 x } - 16 x e ^ { 4 x } = 0$