Find $f \circ g$.
$$f ( x ) = x + 2 \quad g ( x ) = \frac { 5 } { x ^ { 2 } - 4 }$$
A) $( f \circ g ) ( x ) = \frac { 5 } { x ^ { 2 } }$
B) $( f \circ g ) ( x ) = \frac { 5 } { x ^ { 2 } + 4 x }$
C)
$( f \circ g ) ( x ) = \frac { 2 x ^ { 2 } + 3 } { x ^ { 2 } - 4 }$
D) $( f \circ g ) ( x ) = \frac { 7 } { x ^ { 2 } - 4 }$
E)
$( f \circ g ) ( x ) = \frac { 2 x ^ { 2 } - 3 } { x ^ { 2 } - 4 }$

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The Answer of Find $f \circ g$.
$$f ( x ) = x + 2 \quad g ( x ) = \frac { 5 } { x ^ { 2 } - 4 }$$
A) $( f \circ g ) ( x ) = \frac { 5 } { x ^ { 2 } }$
B) $( f \circ g ) ( x ) = \frac { 5 } { x ^ { 2 } + 4 x }$
C)
$( f \circ g ) ( x ) = \frac { 2 x ^ { 2 } + 3 } { x ^ { 2 } - 4 }$
D) $( f \circ g ) ( x ) = \frac { 7 } { x ^ { 2 } - 4 }$
E)
$( f \circ g ) ( x ) = \frac { 2 x ^ { 2 } - 3 } { x ^ { 2 } - 4 }$

Find f∘gf \circ gf∘g f(x)=x+2g(x)=5x2−4f ( x ) = x + 2 \quad g ( x ) = \frac { 5 } { x ^ { 2 } - 4 }f(x)=x+2g(x)=x2−45​

Find $f \circ g$ $f ( x ) = x + 2 \quad g ( x ) = \frac { 5 } { x ^ { 2 } - 4 }$