Boyle's Law says that volume $\mathrm { V }$ of a gas at constant temperature increases whenever the pressure $\mathrm { P }$ decreases, so that $\mathrm { V }$ and $\mathrm { P }$ are inversely proportional. If $\mathrm { P } = 14.1 \mathrm { lbs } / \mathrm { in } ^ { 2 }$ when $\mathrm { V } = 900$ in ${ } ^ { 3 }$, then what is $\mathrm { V }$ when $\mathrm { P } = 21 \mathrm { lbs } /$ in $^ { 2 }$ ?
A) $\frac { 1000 } { 329 }$ in 3
B) $\frac { 329 } { 1000 }$ in $^ { 3 }$
C) $\frac { 4230 } { 7 }$ in 3
D) $\frac { 63000 } { 47 } \mathrm { in } ^ { 3 }$

Question

Quizplus · Accepted Answer

Boyle's Law states that $P_1V_1 = P_2V_2$. Substituting the given values, $14.1 \times 900 = 21 \times V_2$. Solving for $V_2$ gives $V_2 = \frac{14.1 \times 900}{21} = \frac{12690}{21} = \frac{4230}{7}$ in$^3$.

Boyle's Law Says That Volume V\mathrm { V }V Of a Gas at Constant Temperature Increases Whenever the Pressure

Boyle's Law Says That Volume $\mathrm { V }$ Of a Gas at Constant Temperature Increases Whenever the Pressure