Graph the function. -\[f ( x ) = \left\{ \begin{array} { l l } 4 x + 2 , & x 3 \end{array} \right.\]

- For $x 3$, the function is a line with a slope of 3 and a $y$-intercept of $-1$. Therefore, the graph consists of three line segments, and only graph B correctly shows this.

Graph the function. -\[f ( x ) = \left\{ \begin{array} { l l } 4 x + 2 , & x 3 \end{array} \right.\]

- For $x 3$, the function is a line with a slope of 3 and a $y$-intercept of $-1$. Therefore, the graph consists of three line segments, and only graph B correctly shows this.

Solved

Graph the Function $f ( x ) = \left\{ \begin{array} { l l } 4 x + 2 , & x < - 2 \\x , & - 2 \leq x \leq 3 \\3 x - 1 , & x > 3\end{array} \right.$

Question 38

Multiple Choice

Graph the function.
- $f ( x ) = \left\{ \begin{array} { l l } 4 x + 2 , & x < - 2 \\x , & - 2 \leq x \leq 3 \\3 x - 1 , & x > 3\end{array} \right.$
$Graph the function. - f ( x ) = \left\{ \begin{array} { l l } 4 x + 2 , & x < - 2 \\ x , & - 2 \leq x \leq 3 \\ 3 x - 1 , & x > 3 \end{array} \right. A) B) C) D)$

A)
$Graph the function. - f ( x ) = \left\{ \begin{array} { l l } 4 x + 2 , & x < - 2 \\ x , & - 2 \leq x \leq 3 \\ 3 x - 1 , & x > 3 \end{array} \right. A) B) C) D)$
B)
$Graph the function. - f ( x ) = \left\{ \begin{array} { l l } 4 x + 2 , & x < - 2 \\ x , & - 2 \leq x \leq 3 \\ 3 x - 1 , & x > 3 \end{array} \right. A) B) C) D)$
C)
$Graph the function. - f ( x ) = \left\{ \begin{array} { l l } 4 x + 2 , & x < - 2 \\ x , & - 2 \leq x \leq 3 \\ 3 x - 1 , & x > 3 \end{array} \right. A) B) C) D)$
D)
$Graph the function. - f ( x ) = \left\{ \begin{array} { l l } 4 x + 2 , & x < - 2 \\ x , & - 2 \leq x \leq 3 \\ 3 x - 1 , & x > 3 \end{array} \right. A) B) C) D)$