$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
-$$\lim _ { x \rightarrow - 0.5 ^ { - } } \sqrt { \frac { x + 7 } { x + 5 } }$$
A) $\sqrt { \frac { 13 } { 9 } }$
B) $\sqrt { \frac { 15 } { 11 } }$
C) Does not exist
D) $\frac { 15 } { 11 }$

Question

Quizplus · Accepted Answer

As $ x \rightarrow -0.5^- $, the expression inside the square root becomes $\frac{6.5}{4.5}$, which simplifies to $\frac{13}{9}$. The square root of this fraction is $\sqrt{\frac{13}{9}}$, which matches choice B.

Find the limit using lim⁡x=0sin⁡xx=1. \text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. } Find the limit using limx=0​xsinx​=1.

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$