Find the derivative.
-$$r = \frac { 2 } { s ^ { 3 } } - \frac { 8 } { s }$$
A) $- \frac { 6 } { s ^ { 2 } } + \frac { 8 } { s ^ { 2 } }$
B) $\frac { 2 } { s ^ { 4 } } - \frac { 8 } { s ^ { 2 } }$
C) $\frac { 6 } { s ^ { 4 } } - \frac { 8 } { s ^ { 2 } }$
D) $- \frac { 6 } { s ^ { 4 } } + \frac { 8 } { s ^ { 2 } }$

Question

Quizplus · Accepted Answer

The derivative of $r$ with respect to $s$ is found by applying the power rule to each term separately. For the first term, $\frac{d}{ds}(\frac{2}{s^3}) = \frac{d}{ds}(2s^{-3}) = -6s^{-4} = -\frac{6}{s^4}$. For the second term, $\frac{d}{ds}(-\frac{8}{s}) = \frac{d}{ds}(-8s^{-1}) = 8s^{-2} = \frac{8}{s^2}$. Combining these gives $-\frac{6}{s^4} + \frac{8}{s^2}$.

Find the Derivative r=2s3−8sr = \frac { 2 } { s ^ { 3 } } - \frac { 8 } { s }r=s32​−s8​

Find the Derivative $r = \frac { 2 } { s ^ { 3 } } - \frac { 8 } { s }$