Find the indicated derivative.
-$\frac { d p } { d q }$ if $p = \frac { 1 } { \sqrt { q + 1 } }$
A) $\frac { 1 } { 2 ( q + 1 ) \sqrt { q + 1 } }$
B) $- \frac { 1 } { ( q + 1 ) \sqrt { q + 1 } }$
C) $- \frac { 1 } { 2 \sqrt { q + 1 } }$
D) $- \frac { 1 } { 2 ( q + 1 ) \sqrt { q + 1 } }$

Question

Quizplus · Accepted Answer

To find the derivative of $p = \frac { 1 } { \sqrt { q + 1 } }$, we rewrite $p$ as $p = (q + 1)^{-1/2}$. Using the chain rule, the derivative is $\frac { d p } { d q } = -\frac{1}{2}(q + 1)^{-3/2} = - \frac { 1 } { 2 ( q + 1 ) \sqrt { q + 1 } }$.

Find the Indicated Derivative dpdq\frac { d p } { d q }dqdp​

Find the Indicated Derivative $\frac { d p } { d q }$