Solve the differential equation.
-$$x \frac { d y } { d x } = \frac { \cos x } { x ^ { 5 } } - 6 y , x 0$$
A) $y = x ^ { - 6 } ( \cos x + C ) , x 0$
B) $y = x ^ { 6 } ( \sin x + C ) , x 0$
C) $y = x ^ { 6 } ( \cos x + C ) , x 0$
D) $y = x ^ { - 6 } ( \sin x + C ) , x 0$

Question

Solve the differential equation.
-$$x \frac { d y } { d x } = \frac { \cos x } { x ^ { 5 } } - 6 y , x > 0$$
A) $y = x ^ { - 6 } ( \cos x + C ) , x > 0$
B) $y = x ^ { 6 } ( \sin x + C ) , x > 0$
C) $y = x ^ { 6 } ( \cos x + C ) , x > 0$
D) $y = x ^ { - 6 } ( \sin x + C ) , x > 0$

Quizplus · Accepted Answer

The Answer of Solve the differential equation.
-$$x \frac { d y } { d x } = \frac { \cos x } { x ^ { 5 } } - 6 y , x > 0$$
A) $y = x ^ { - 6 } ( \cos x + C ) , x > 0$
B) $y = x ^ { 6 } ( \sin x + C ) , x > 0$
C) $y = x ^ { 6 } ( \cos x + C ) , x > 0$
D) $y = x ^ { - 6 } ( \sin x + C ) , x > 0$

Solve the Differential Equation xdydx=cos⁡xx5−6y,x>0x \frac { d y } { d x } = \frac { \cos x } { x ^ { 5 } } - 6 y , x > 0xdxdy​=x5cosx​−6y,x>0

Solve the Differential Equation $x \frac { d y } { d x } = \frac { \cos x } { x ^ { 5 } } - 6 y , x > 0$