A deuteron is accelerated from rest through a 10-kV potential difference and then moves perpendicularly to a uniform magnetic field with B = 1.6 T. What is the radius of the resulting circular path? (deuteron: m = 3.3 × 10−27 kg, q = 1.6 × 10−19 C)
A)19 mm
B)13 mm
C)20 mm
D)10 mm
E)9.0 mm

Question

Quizplus · Accepted Answer

The radius of the circular path can be calculated using the formula r = mv/qB. First, find the velocity using the kinetic energy gained from the potential difference: KE = qV = 1/2 mv^2. Solving for v gives v = sqrt(2qV/m). Substituting the given values and solving for r gives approximately 13 mm.

A Deuteron Is Accelerated from Rest Through a 10-KV Potential