A Super Ball rebounds to approximately 91% of the height from which it is dropped.If the ball is dropped from a height of 8 meters, how high will it rebound after the 17th bounce?
A)1.61 meters
B)146.50 meters
C)2.01 meters
D)2.41 meters
E)2.61 meters

Question

Quizplus · Accepted Answer

The height of the rebound after each bounce is 91% of the height from the previous bounce. This can be calculated using the formula for geometric sequences: $h_n = h_0 \times r^{(n-1)}$, where $h_n$ is the height after the nth bounce, $h_0$ is the initial height, $r$ is the common ratio (in this case, 0.91), and $n$ is the number of bounces. Plugging in the values: $h_{17} = 8 \times 0.91^{16}$, which approximately equals 1.61 meters.

A Super Ball Rebounds to Approximately 91% of the Height