One root of the equation $x \left( 3 x ^ { 3 } - 2 \right) = 7 x$ is 0 . How many other roots are there?
A) 4
B) none of these
C) 3
$\begin{array} { l l } \text { d. } & 2 \ \text { e. } & 0 \end{array}$

Question

Quizplus · Accepted Answer

We are given one root as 0, so we need to solve the equation for the remaining roots. Dividing both sides by x, we get $$3x^3-2 =7.$$ Simplifying, we get $$x^3 =3.$$ So, there are three real roots to the equation: one at 0 (which given in the problem), and two others. Therefore, the answer is 3.

One Root of the Equation x(3x3−2)=7xx \left( 3 x ^ { 3 } - 2 \right) = 7 xx(3x3−2)=7x

One Root of the Equation $x \left( 3 x ^ { 3 } - 2 \right) = 7 x$