A Wisconsin lake is stocked with 10,000 bluegill. The population is expected to grow exponentially according to the model $P = P _ { 0 } 2 ^ { t / 2 }$. How many bluegill will be in the lake in 6 years?
A)120,000 bluegill
B)40,000 bluegill
C)80,000 bluegill
D)60,000 bluegill
E)12,599 bluegill

Question

A Wisconsin lake is stocked with 10,000 bluegill. The population is expected to grow exponentially according to the model $P = P _ { 0 } 2 ^ { t / 2 }$. How many bluegill will be in the lake in 6 years?
A)120,000 bluegill 
B)40,000 bluegill 
C)80,000 bluegill 
D)60,000 bluegill 
E)12,599 bluegill 
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Quizplus · Accepted Answer

Using the exponential growth model, we can substitute t = 6 years and P₀ = 10,000 to obtain:
P = 10,000(2)^(6/2)
P = 10,000(2)^3
P = 10,000(8)
P = 80,000
Therefore, there will be 80,000 bluegill in the lake in 6 years. So, the correct choice is C.

A Wisconsin Lake Is Stocked with 10,000 Bluegill P=P02t/2P = P _ { 0 } 2 ^ { t / 2 }P=P0​2t/2

A Wisconsin Lake Is Stocked with 10,000 Bluegill $P = P _ { 0 } 2 ^ { t / 2 }$