Find the vertex of the parabola. $y = 3 x ^ { 2 } - 2$
A) $\quad ( - 2,0 )$
B) $\quad ( - 2,3 )$
C) $\quad ( 0,3 )$
D) $\quad ( 3 , - 2 )$
E) $\quad ( 0 , - 2 )$

Question

Quizplus · Accepted Answer

The vertex form of a parabola is $y = a(x - h)^2 + k$, where $(h, k)$ is the vertex. For $y = 3x^2 - 2$, the equation is already centered at $x = 0$, so $h = 0$, and $k = -2$, making the vertex $(0, -2)$.

Find the Vertex of the Parabola y=3x2−2y = 3 x ^ { 2 } - 2y=3x2−2

Find the Vertex of the Parabola $y = 3 x ^ { 2 } - 2$