Suppose a gun with a muzzle velocity of 1200 feet per second is fired at an angle of $4 ^ { \circ }$ above the horizontal. Find the horizontal component of the velocity. Round your answer to two decimal places.
A) $1,240.08 \mathrm { ft } / \mathrm { sec }$
B) $2,395.15 \mathrm { ft } / \mathrm { sec }$
C) $1,197.08 \mathrm { ft } / \mathrm { sec }$
D) $2,393.15 \mathrm { ft } / \mathrm { sec }$
E) $1,209.08 \mathrm { ft } / \mathrm { sec }$

Question

Quizplus · Accepted Answer

The horizontal component of the velocity can be found using the formula: 
$$\text{Horizontal velocity} = \text{Muzzle velocity} \cos \theta$$
where $\theta$ is the angle of elevation above the horizontal. 
Substituting the given values, we get: 
$$\text{Horizontal velocity} = 1200 \cos 4^\circ \approx 1,197.08 \text{ ft/sec}$$
Rounding to two decimal places, we get the final answer as choice C: $1,197.08$ ft/sec.

Suppose a Gun with a Muzzle Velocity of 1200 Feet 4∘4 ^ { \circ }4∘

Suppose a Gun with a Muzzle Velocity of 1200 Feet $4 ^ { \circ }$