Find the center of the ellipse given by $$16 x ^ { 2 } + y ^ { 2 } = 16$$
A) $( 0,4 )$
B) $( 0 , - 4 )$
C) $( 0,0 )$
D) $( - 4,0 )$
E) $( 4,0 )$

Name: Find the center of the ellipse given by \[16 x ^ { 2 } + y ^ { 2 } = 16\] A) $( 0,4 )$ B) $( 0 , - 4 )$ C) $( 0,0 )$ D) $( - 4,0 )$ E) $( 4,0 )$
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Question

Quizplus · Accepted Answer

The center of an ellipse in the form $Ax^2 + By^2 = C$ is at the origin $(0,0)$ when not shifted by any terms involving $x$ or $y$. The given equation fits this form without any shifts.

Find the Center of the Ellipse Given By 16x2+y2=1616 x ^ { 2 } + y ^ { 2 } = 1616x2+y2=16

Find the Center of the Ellipse Given By $16 x ^ { 2 } + y ^ { 2 } = 16$