The maker of an automobile advertises that it takes $13 \text { seconds to accelerate from } 25$ kilometers per hour to 75 kilometers per hour. Assuming constant acceleration, compute the distance, in meters, the car travels during the 13 seconds. Round your answer to two decimal places.
A) $27.69 \mathrm {~m}$
B) $361.11 \mathrm {~m}$
C) $180.56 \mathrm {~m}$
D) $234.72 \mathrm {~m}$
E) $90.28 \mathrm {~m}$

Question

Quizplus · Accepted Answer

To find the distance, use the formula $d = v_i t + \frac{1}{2} a t^2$. Convert speeds to m/s: $25 \text{ km/h} = 6.94 \text{ m/s}$ and $75 \text{ km/h} = 20.83 \text{ m/s}$. Find acceleration $a = \frac{20.83 - 6.94}{13} = 1.07 \text{ m/s}^2$. Then, $d = 6.94 \times 13 + \frac{1}{2} \times 1.07 \times 13^2 = 180.56 \text{ m}$.

The Maker of an Automobile Advertises That It Takes 13 seconds to accelerate from 2513 \text { seconds to accelerate from } 2513 seconds to accelerate from 25

The Maker of an Automobile Advertises That It Takes $13 \text { seconds to accelerate from } 25$