$\text { A point is moving along the graph of the function } y = \frac { 1 } { 9 x ^ { 2 } + 4 } \text { such that } \frac { d x } { d t } = 2$ centimeters per second. Find $\frac { d y } { d t }$ when $x = 2$.
A) $\frac { d y } { d t } = - \frac { 9 } { 5 }$
B) $\frac { d y } { d t } = \frac { 9 } { 200 }$
C) $\frac { d y } { d t } = \frac { 9 } { 400 }$
D) $\frac { d y } { d t } = - \frac { 9 } { 400 }$
E) $\frac { d y } { d t } = - \frac { 9 } { 200 }$

Question

$\text { A point is moving along the graph of the function } y = \frac { 1 } { 9 x ^ { 2 } + 4 } \text { such that } \frac { d x } { d t } = 2$ centimeters per second. Find $\frac { d y } { d t }$ when $x = 2$.
A) $\frac { d y } { d t } = - \frac { 9 } { 5 }$
B) $\frac { d y } { d t } = \frac { 9 } { 200 }$ 
C) $\frac { d y } { d t } = \frac { 9 } { 400 }$
D) $\frac { d y } { d t } = - \frac { 9 } { 400 }$
E) $\frac { d y } { d t } = - \frac { 9 } { 200 }$

Quizplus · Accepted Answer

The Answer of $\text { A point is moving along the graph of the function } y = \frac { 1 } { 9 x ^ { 2 } + 4 } \text { such that } \frac { d x } { d t } = 2$ centimeters per second. Find $\frac { d y } { d t }$ when $x = 2$.
A) $\frac { d y } { d t } = - \frac { 9 } { 5 }$
B) $\frac { d y } { d t } = \frac { 9 } { 200 }$ 
C) $\frac { d y } { d t } = \frac { 9 } { 400 }$
D) $\frac { d y } { d t } = - \frac { 9 } { 400 }$
E) $\frac { d y } { d t } = - \frac { 9 } { 200 }$

A point is moving along the graph of the function y=19x2+4 such that dxdt=2\text { A point is moving along the graph of the function } y = \frac { 1 } { 9 x ^ { 2 } + 4 } \text { such that } \frac { d x } { d t } = 2 A point is moving along the graph of the function y=9x2+41​ such that dtdx​=2

$\text { A point is moving along the graph of the function } y = \frac { 1 } { 9 x ^ { 2 } + 4 } \text { such that } \frac { d x } { d t } = 2$