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Question 136
Use implicit differentiation to find dydx\text { Use implicit differentiation to find } \frac { d y } { d x } Use implicit differentiation to find dxdy 7exy+5y2=77 e ^ { x y } + 5 y ^ { 2 } = 77exy+5y2=7
A) dydx=−7exy7exyx−10y\frac { d y } { d x } = - \frac { 7 e ^ { x y } } { 7 e ^ { x y } x - 10 y }dxdy=−7exyx−10y7exy B) dydx=−7yexy7exyx+10y\frac { d y } { d x } = - \frac { 7 y e ^ { x y } } { 7 e ^ { x y } x + 10 y }dxdy=−7exyx+10y7yexy C) dydx=7yexy7exy−10y\frac { d y } { d x } = \frac { 7 y e ^ { x y } } { 7 e ^ { x y } - 10 y }dxdy=7exy−10y7yexy D) dydx=−7yexy7exyx+5y\frac { d y } { d x } = - \frac { 7 y e ^ { x y } } { 7 e ^ { x y } x + 5 y }dxdy=−7exyx+5y7yexy E) dydx=7yexy7exy+10y\frac { d y } { d x } = \frac { 7 y e ^ { x y } } { 7 e ^ { x y } + 10 y }dxdy=7exy+10y7yexy
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