Find the limit (if it exists). $$\lim _ { x \rightarrow - 8 } \frac { x + 8 } { x ^ { 2 } - 64 }$$
A) $- \frac { 1 } { 16 }$
B) $- \frac { 1 } { 32 }$
C) $- 32$
D) $- 8$
E) $\frac { 1 } { 16 }$

Question

Quizplus · Accepted Answer

The given limit can be simplified by factoring the denominator as $\lim _ { x \rightarrow - 8 } \frac { x + 8 } { (x + 8)(x - 8) }$. Canceling the $x + 8$ terms gives $\lim _ { x \rightarrow - 8 } \frac { 1 } { x - 8 }$, which evaluates to $-\frac{1}{16}$ when $x = -8$.

Find the Limit (If It Exists) lim⁡x→−8x+8x2−64\lim _ { x \rightarrow - 8 } \frac { x + 8 } { x ^ { 2 } - 64 }x→−8lim​x2−64x+8​

Find the Limit (If It Exists) $\lim _ { x \rightarrow - 8 } \frac { x + 8 } { x ^ { 2 } - 64 }$