$\text { Let } f ( x ) = x ^ { 2 } - x - 5 \text { and } g ( x ) = \sqrt [ 3 ] { x + 14 } \text {. Find the limits. }$ $\lim _ { x \rightarrow 3 } g ( f ( x ) )$
A) $- \sqrt [ 3 ] { 1 }$
B) $\sqrt [ 3 ] { 29 }$
C) $- \sqrt [ 3 ] { 15 }$
D) $\sqrt [ 3 ] { 15 }$
E) $\sqrt [ 3 ] { 1 }$

Question

Quizplus · Accepted Answer

First, calculate $f(3) = 3^2 - 3 - 5 = 9 - 3 - 5 = 1$. Then, plug this into $g(x)$ to get $g(f(3)) = g(1) = \sqrt[3]{1 + 14} = \sqrt[3]{15}$.

Let f(x)=x2−x−5 and g(x)=x+143. Find the limits. \text { Let } f ( x ) = x ^ { 2 } - x - 5 \text { and } g ( x ) = \sqrt [ 3 ] { x + 14 } \text {. Find the limits. } Let f(x)=x2−x−5 and g(x)=3x+14​. Find the limits.

$\text { Let } f ( x ) = x ^ { 2 } - x - 5 \text { and } g ( x ) = \sqrt [ 3 ] { x + 14 } \text {. Find the limits. }$