Vx is the velocity of a particle moving along the x axis as shown. If x = 2.0 m at t = 1.0 s, what is the position of the particle at t = 6.0 s?
A)(-2.0 m)
B)+2.0 m
C)+1.0 m
D)(-1.0 m)
E)6.0 m

Question

Vx is the velocity of a particle moving along the x axis as shown. If x = 2.0 m at t = 1.0 s, what is the position of the particle at t = 6.0 s? 
A)(-2.0 m) 
B)+2.0 m 
C)+1.0 m 
D)(-1.0 m) 
E)6.0 m

Quizplus · Accepted Answer

This problem involves using the equation of motion for constant acceleration in one dimension: 
x = x0 + v0t + (1/2)at^2 
Since the particle is only moving in the x direction, we can simplify this to: 
x = x0 + vx t 
where vx is the velocity in the x direction. 
We are given that x0 = 0 (the initial position) since the particle is not moving at t = 0. We are also given that vx = 2.0 m/s, so: 
x = (2.0 m/s)(6.0 s) 
x = 12 m 
However, we need to pay attention to the sign of x. Since the particle is moving in the positive x direction (to the right), the position at t = 6.0 s will be positive relative to the initial position. Therefore, the answer is: 
D) (S1-S102.0 m)

Vx Is the Velocity of a Particle Moving Along the X