In a location where the train tracks run parallel to a road, a sports car travelling at 60 m/s passes a freight train travelling at 30 m/s. How long does it take for the car to be 180 m ahead of the train?
A)2.0 s
B)3.0 s
C)6.0 s
D)9.0 s
E)18.0 s

Question

Quizplus · Accepted Answer

The relative speed of the car with respect to the train is 60 m/s - 30 m/s = 30 m/s. To be 180 m ahead, it takes 180 m / 30 m/s = 6.0 s.

In a Location Where the Train Tracks Run Parallel to a Road