The speed of a 2.0-kg object changes from 30 m/s to 40 m/s during a 5.0-s time interval.During this same time interval,the velocity of the object changes its direction by 90$\degree$.What is the magnitude of the average total force acting on the object during this time interval?
A)30 N
B)20 N
C)40 N
D)50 N
E)6.0 N

Question

Quizplus · Accepted Answer

First, we need to find the acceleration of the object using the given information.

Acceleration = (change in velocity) / (time interval) 
Acceleration = (40 m/s - 30 m/s) / 5.0 s 
Acceleration = 2.0 m/s^2

Next, we need to find the net force acting on the object.

Net force = (mass) x (acceleration) 
Net force = (2.0 kg) x (2.0 m/s^2) 
Net force = 4.0 N

However, the problem asks for the average total force. Since the direction of the velocity changes by 90 degrees during the time interval, we know that the force acting on the object must also change direction by 90 degrees in order to cause the change in direction of the velocity.

Therefore, we can calculate the average total force using:

Average force = (net force) / sin(theta) 
Where theta = 90 degrees

Average force = (4.0 N) / sin(90 degrees) 
Average force = 4.0 N / 1 
Average force = 4.0 N

So the magnitude of the average total force acting on the object during this time interval is 4.0 N, which corresponds to choice B.

The Speed of a 2 °\degree° What Is the Magnitude of the Average Total Force Acting

The Speed of a 2 $\degree$ What Is the Magnitude of the Average Total Force Acting