Knowing that $g=9.80 \frac{\mathrm{~m}}{\mathrm{~s}^{2}}$ at sea level and that RE = 6.37 * 106 m, we find that the value of g in $\frac{\mathrm{m}}{\mathrm{~s}^{2}}$ at a distance RE from the surface of the Earth is:
A)1.23.
B)2.45.
C)4.90.
D)7.35.
E)9.80.

Question

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The Answer of Knowing that $g=9.80 \frac{\mathrm{~m}}{\mathrm{~s}^{2}}$ at sea level and that RE = 6.37 * 106 m, we find that the value of g in $\frac{\mathrm{m}}{\mathrm{~s}^{2}}$ at a distance RE from the surface of the Earth is:
A)1.23.
B)2.45.
C)4.90.
D)7.35.
E)9.80.

Knowing That g=9.80 m s2g=9.80 \frac{\mathrm{~m}}{\mathrm{~s}^{2}}g=9.80 s2 m​ At Sea Level and That RE = 6

Knowing That $g=9.80 \frac{\mathrm{~m}}{\mathrm{~s}^{2}}$ At Sea Level and That RE = 6