In the figure, if Q = 30 $\mu$C, q = 5.0 $\mu$C, and d = 30 cm, what is the magnitude of the electrostatic force on q?
A)15 N
B)23 N
C)zero
D)7.5 N
E)38 N

Question

In the figure, if Q = 30 $\mu$C, q = 5.0 $\mu$C, and d = 30 cm, what is the magnitude of the electrostatic force on q? 
A)15 N 
B)23 N 
C)zero 
D)7.5 N 
E)38 N

Quizplus · Accepted Answer

The electrostatic force can be calculated using Coulomb's Law: 
$F=\frac{kQq}{d^2}$ where k is the Coulomb constant and d is the distance between the charges. Plugging in the given values, we get: 
$F=\frac{(9	imes 10^9)(30	ext{ }\mu	ext{C})(5	ext{ }\mu	ext{C})}{(0.3	ext{ m})^2}=7.5	ext{ N}$ 
Therefore, the magnitude of the electrostatic force on q is 7.5 N.

In the Figure, If Q = 30 μ\muμ C, Q = 50

In the Figure, If Q = 30 $\mu$ C, Q = 50