How much energy is in a 63 kHz photon of AM-radiation?
A)1.0 *10-38 J
B)6.6 * 10-30 J
C)4.2 * 10-29 J
D)3.1 *10-30 J
E)13 *10-29 J

Question

Quizplus · Accepted Answer

The energy of a photon is given by E = hf, where h is Planck's constant and f is the frequency of radiation. Substituting the given frequency of 63 kHz (or 6.3 x 10^4 Hz) and Planck's constant (6.626 x 10^-34 J s) into the equation, we get E = (6.626 x 10^-34 J s)(6.3 x 10^4 Hz) = 4.18 x 10^-29 J, which is closest to choice C of 4.2 x 10^-29 J.

How Much Energy Is in a 63 KHz Photon of AM-Radiation