0.50 mole of NaCl , a strong electrolyte, is added to 1.0 kg of water. The freezing point of the solution will be

Question

0.50  mole of NaCl , a strong electrolyte, is added to  1.0 kg of water. The freezing point of the solution will be

Quizplus · Accepted Answer

When 0.50 mole of NaCl is added to 1.0 kg of water, the molality of the solution can be calculated as follows:

molality (m) = moles of solute / mass of solvent in kg
= 0.50 / 1.0
= 0.50 mol/kg

The freezing point depression (ΔTf) of the solution can be calculated using the formula:

ΔTf = Kf × m

where Kf is the freezing point depression constant of water, which is 1.86 °C/m.

ΔTf = 1.86 × 0.50
= 0.93 °C

Therefore, the freezing point of the solution will be lowered by 0.93 °C.

The freezing point of pure water is 0 °C, so the freezing point of the solution will be:

0 °C - 0.93 °C = -0.93 °C

However, freezing point cannot be negative so we report our answer as 11ec7dd7_d7ba_8b08_8044_9175d4fcd178_TB34225555_11.

050 Mole of NaCl , a Strong Electrolyte, Is