What volume of a 2.00 M KCl solution is required to prepare 500. mL of a 0.100 M KCl solution?
B) 2.00 mL
C) 25.0 mL
E) 0.0400 mL

Question

What volume of a 2.00 M KCl solution is required to prepare 500. mL of a 0.100 M KCl solution? 
B) 2.00 mL 
C) 25.0 mL 
E) 0.0400 mL

Quizplus · Accepted Answer

The formula for dilution is M1V1 = M2V2.
M1 = 2.00 M (initial concentration of KCl solution)
V1 = unknown volume (what we're solving for)
M2 = 0.100 M (final concentration of KCl solution)
V2 = 500. mL (final volume of KCl solution)
Plugging in the values, we get:
2.00 M x V1 = 0.100 M x 500. mL
V1 = (0.100 M x 500. mL) / 2.00 M
V1 = 25.0 mL, which is option C. Therefore, C is the correct answer.

What Volume of a 2