The overall phase angle of a parallel circuit with a resistance of 20 $\Omega$ and an inductive reactance of 25 $\mathrm { k } \Omega$ would be nearly 90 degrees.

Question

The overall phase angle of a parallel circuit with a resistance of  20 $\Omega$  and an inductive reactance of  25 $\mathrm { k } \Omega$  would be nearly 90 degrees.

Quizplus · Accepted Answer

The phase angle of a parallel circuit can be calculated using the formula tan-1(X/R), where X is the reactance and R is the resistance. In this case, tan-1(25kΩ/20Ω) gives a phase angle of approximately 83 degrees, not close to 90 degrees.

The Overall Phase Angle of a Parallel Circuit with a Resistance