What is the bandwidth of the resonant circuit if the resonant frequency is 1.42 MHz , the inductive reactance is 3.5 $\mathrm { k } \Omega$ and the coil's resistance is 8 ohm ?
A) 32.5 kHz
B) 3.25 kHz
C) 1.42 MHz
D) 2285 Hz

Question

What is the bandwidth of the resonant circuit if the resonant frequency is  1.42 MHz , the inductive reactance is  3.5  $\mathrm { k } \Omega$ and the coil's resistance is  8 ohm  ?
A)  32.5 kHz
B)  3.25 kHz
C)  1.42 MHz
D)  2285 Hz

Quizplus · Accepted Answer

The bandwidth of the resonant circuit can be calculated using the formula:

Bandwidth = Resonant frequency / Q factor

The Q factor can be calculated using the formula:

Q = X L / R

where X L is the inductive reactance and R is the resistance.

Substituting the given values:

Q = (3.5 kΩ)/(8Ω) = 437.5

Bandwidth = (1.42 MHz)/Q = (1.42 MHz)/(437.5) = 3.25 kHz

Therefore, the bandwidth of the resonant circuit is 3.25 kHz. The best choice is option B.

What Is the Bandwidth of the Resonant Circuit If the Resonant