$$\text { Figure 6'5 }$$ -Refer to Figure 6-5. Determine the amount of current flow through R₂ with the following component parameters. V_S1=10 V, V_S2=3 V, R₁=2 k, R₂=3k , and R₃=700 A) 5.3 mA B) 1 mA C) 1.37 mA D) 0 A

Question

Quizplus · Accepted Answer

First, we can use voltage division to find the voltage at point S1U1B12:

VR12 = VS1U1B1S1S1U1B0 * (RS1U1B12S1U1B0/(RS1U1B11S1U1B0+RS1U1B12S1U1B0+RS1U1B13S1U1B0)) + VS1U1B1S2S1U1B0 * (RS1U1B13S1U1B0/(RS1U1B11S1U1B0+RS1U1B12S1U1B0+RS1U1B13S1U1B0))
VR12 = 10 * (3000/(2000+3000+700)) + 3 * (700/(2000+3000+700))
VR12 = 5.29 V

Next, we can use Ohm's Law to find the current through RS1U1B12S1U1B0:

IR12 = VR12 / RS1U1B12S1U1B0
IR12 = 5.29 / 3000
IR12 = 1.43 mA

Therefore, the answer is C) 1.37 mA (rounded to two decimal places).

Figure 6’5 \text { Figure 6'5 } Figure 6’5 -Refer to Figure 6-5

$\text { Figure 6'5 }$ -Refer to Figure 6-5