Solve the problem.
-How many liters of a 30% alcohol solution must be mixed with 90 liters of a 80% solution to get a 60% solution?
A) 150 L
B) 6 L
C) 60 L
D) 15 L

Name: Solve the problem. -How many liters of a 30% alcohol solution must be mixed with 90 liters of a 80% solution to get a 60% solution? A) 150 L B) 6 L C) 60 L D) 15 L
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Question

Quizplus · Accepted Answer

To find the amount of 30% solution needed, set up the equation: 0.3x + 0.8(90) = 0.6(x + 90). Solving for x gives x = 60 liters.

Solve the Problem. -How Many Liters of a 30% Alcohol Solution Must Be