Find the inverse of the function.
-$$f ( x ) = \frac { 8 } { x + 2 }$$
A) $f ^ { - 1 } ( x ) = \frac { x } { 2 + 8 x }$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 2 + 8 \mathrm { x } } { \mathrm { x } }$
C) $f ^ { - 1 } ( x ) = \frac { - 2 x + 8 } { x }$
D) Not invertible

Question

Quizplus · Accepted Answer

To find the inverse, swap $x$ and $y$ in the equation $y = \frac{8}{x+2}$ and solve for $y$. This gives $x = \frac{8}{y+2}$, leading to $y = \frac{-2x + 8}{x}$.

Find the Inverse of the Function f(x)=8x+2f ( x ) = \frac { 8 } { x + 2 }f(x)=x+28​

Find the Inverse of the Function $f ( x ) = \frac { 8 } { x + 2 }$