Find f(x) and g(x) so that the function can be described as y = f(g(x)).
-$$y = \frac { 7 } { x ^ { 2 } } + 9$$
A) $f ( x ) = x , g ( x ) = \frac { 7 } { x } + 9$
B) $f ( x ) = \frac { 7 } { x ^ { 2 } } , g ( x ) = 9$
C) $f ( x ) = \frac { 1 } { x } , g ( x ) = \frac { 7 } { x } + 9$
D) $f ( x ) = x + 9 , g ( x ) = \frac { 7 } { x ^ { 2 } }$

Question

Quizplus · Accepted Answer

The correct choice is D because $f(g(x))$ means that $g(x)$ is first applied and then $f(x)$ is applied to the result of $g(x)$. Here, $g(x) = \frac{7}{x^2}$ is the inner function that transforms $x$ first, and then $f(x) = x + 9$ is the outer function that adds 9 to the result of $g(x)$, matching the original function $y = \frac{7}{x^2} + 9$.

Find F(x) and G(x) So That the Function Can Be y=7x2+9y = \frac { 7 } { x ^ { 2 } } + 9y=x27​+9

Find F(x) and G(x) So That the Function Can Be $y = \frac { 7 } { x ^ { 2 } } + 9$