Determine algebraically whether the function is even, odd, or neither even nor odd.
-$$f ( x ) = \sqrt { x ^ { 2 } + 6 }$$
A) Odd
B) Even
C) Neither

Name: Determine algebraically whether the function is even, odd, or neither even nor odd. -\[f ( x ) = \sqrt { x ^ { 2 } + 6 }\] A) Odd B) Even C) Neither
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Question

Quizplus · Accepted Answer

The function $f(x) = \sqrt{x^2 + 6}$ is even because $f(-x) = \sqrt{(-x)^2 + 6} = \sqrt{x^2 + 6} = f(x)$, which satisfies the definition of an even function.

Determine Algebraically Whether the Function Is Even, Odd, or Neither f(x)=x2+6f ( x ) = \sqrt { x ^ { 2 } + 6 }f(x)=x2+6​

Determine Algebraically Whether the Function Is Even, Odd, or Neither $f ( x ) = \sqrt { x ^ { 2 } + 6 }$