Find the range of the function.
-$$f ( x ) = 3 + \sqrt { 8 - x }$$
A) $[ 8 , \infty )$
B) $[ 3 , \infty )$
C) $( - \infty , 3 ]$
D) $( - \infty , \infty )$

Question

Quizplus · Accepted Answer

The square root function $\sqrt{8-x}$ has a domain of $x \leq 8$ and a range of $[0, \infty)$. Adding 3 to the square root function shifts its range up by 3 units, making the range of $f(x) = 3 + \sqrt{8-x}$ equal to $[3, \infty)$.

Find the Range of the Function f(x)=3+8−xf ( x ) = 3 + \sqrt { 8 - x }f(x)=3+8−x​

Find the Range of the Function $f ( x ) = 3 + \sqrt { 8 - x }$