Eleven dimes dated 1989 through 1999 are tossed. Find the probability of the event.
-Exactly 2 heads
A) 10922048
B) 204855
C) 12
D) 20481

Question

Quizplus · Accepted Answer

The probability of getting exactly 2 heads out of 11 tosses can be calculated using the binomial coefficient, which is C(n, k) = n! / [k!(n-k)!], where n is the total number of trials (in this case, 11 tosses), and k is the number of successful outcomes (in this case, 2 heads). The formula gives us C(11, 2) = 11! / [2!(11-2)!] = 55. However, the correct answer involves not just the binomial coefficient but also considering the total number of outcomes (2^11, since each toss has 2 possible outcomes) and the probability of each outcome. The provided answer choices seem to be incorrect or not directly related to the probability calculation as typically expected (e.g., a fraction or decimal representing the probability). The correct approach would involve calculating the probability and then possibly multiplying by the total number of outcomes to get the number of ways to achieve exactly 2 heads, but none of the provided choices directly match the expected calculation for a probability question.

Eleven Dimes Dated 1989 Through 1999 Are Tossed