Solve the problem.
-A toy rocket is launched straight up from level ground. Its velocity function is $\mathrm { f } ( \mathrm { t } ) = 189 - 32 \mathrm { t } \mathrm { ft } / \mathrm { sec }$, where $\mathrm { t }$ is the number of seconds after launch. At what time does the rocket reach its maximum height?
A) $6.23 \mathrm { sec }$
B) $5.72 \mathrm { sec }$
C) $5.91 \mathrm { sec }$
D) $11.81 \mathrm { sec }$

Question

Quizplus · Accepted Answer

The rocket reaches its maximum height when its velocity is zero. Setting $189 - 32t = 0$ and solving for $t$, we get $t = 5.91$ seconds.

Solve the Problem f(t)=189−32tft/sec\mathrm { f } ( \mathrm { t } ) = 189 - 32 \mathrm { t } \mathrm { ft } / \mathrm { sec }f(t)=189−32tft/sec

Solve the Problem $\mathrm { f } ( \mathrm { t } ) = 189 - 32 \mathrm { t } \mathrm { ft } / \mathrm { sec }$