Solve the problem.
-A ball is tossed straight up from level ground. The velocity of the ball at any time t (sec) is v(t) = 68 - 32t ft/sec. Find how far the ball has traveled at its maximum height.
A) 9 ft
B) 72 ft
C) 63 ft
D) 96 ft

Question

Quizplus · Accepted Answer

The maximum height is reached when the velocity is 0. Setting v(t) = 0 gives 0 = 68 - 32t, solving for t gives t = 68/32 = 2.125 seconds. The distance traveled is found by integrating the velocity function from 0 to 2.125. The integral of v(t) = 68 - 32t dt from 0 to 2.125 is [68t - 16t^2] evaluated from 0 to 2.125, which equals 68(2.125) - 16(2.125)^2 = 144.5 - 72.5 = 72 ft.

Solve the Problem. -A Ball Is Tossed Straight Up from Level Ground. the Level