Solve the inequality.
-$$3 + \frac { 14 } { x } - \frac { 5 } { x ^ { 2 } } \leq 0$$
A) $\left[ - 5 , \frac { 1 } { 3 } \right]$
B) $( - \infty , - 5 ] \cup \left[ \frac { 1 } { 3 } , \infty \right)$
C) $[ - 5,0 ) \cup \left( 0 , \frac { 1 } { 3 } \right]$
D) $\left[ \frac { 1 } { 3 } , 5 \right]$

Question

Quizplus · Accepted Answer

The inequality simplifies to $(x+5)(3x-1) \leq 0$, which holds for $x \in [-5,0) \cup (0, \frac{1}{3}]$.

Solve the Inequality 3+14x−5x2≤03 + \frac { 14 } { x } - \frac { 5 } { x ^ { 2 } } \leq 03+x14​−x25​≤0

Solve the Inequality $3 + \frac { 14 } { x } - \frac { 5 } { x ^ { 2 } } \leq 0$