Use limits to describe the behavior of the rational function near the indicated asymptote.
-$$f ( x ) = - \frac { 8 } { x + 2 }$$
Describe the behavior of the function near its vertical asymptote.
A) $\lim _ { x \rightarrow 2 ^ { - } } f ( x ) = \infty , \lim _ { x \rightarrow 2 ^ { + } } f ( x ) = \infty$
B) $\lim _ { x \rightarrow 2 ^ { - } } f ( x ) = \infty , \lim _ { x \rightarrow 2 ^ { + } } f ( x ) = - \infty$
C) $\lim _ { x \rightarrow 2 ^ { - } } f ( x ) = \infty , \lim _ { x \rightarrow 2 ^ { + } } f ( x ) = - \infty$.
D) $\lim _ { x \rightarrow 2 ^ { - } } f ( x ) = 0 , \quad \lim _ { x \rightarrow 2 ^ { + } } f ( x ) = 0$

Question

Quizplus · Accepted Answer

The vertical asymptote occurs at $x = -2$. As $x$ approaches $-2$ from the left ($x \to -2^-$), the function approaches $\infty$, and as $x$ approaches $-2$ from the right ($x \to -2^+$), the function approaches $-\infty$.

Use Limits to Describe the Behavior of the Rational Function f(x)=−8x+2f ( x ) = - \frac { 8 } { x + 2 }f(x)=−x+28​

Use Limits to Describe the Behavior of the Rational Function $f ( x ) = - \frac { 8 } { x + 2 }$