Use synthetic division to determine whether the number k is an upper or lower bound (as specified) for the real zeros of
the function f.
-$\mathrm { k } = 1 ; \mathrm { f } ( \mathrm { x } ) = 5 \mathrm { x } ^ { 3 } + 7 \mathrm { x } ^ { 2 } + 4 \mathrm { x } + 6$; Upper bound?

Question

Quizplus · Accepted Answer

Since the last number in the quotient is positive, 1 is an upper bound for the real zeros of f.

Use Synthetic Division to Determine Whether the Number K Is k=1;f(x)=5x3+7x2+4x+6\mathrm { k } = 1 ; \mathrm { f } ( \mathrm { x } ) = 5 \mathrm { x } ^ { 3 } + 7 \mathrm { x } ^ { 2 } + 4 \mathrm { x } + 6k=1;f(x)=5x3+7x2+4x+6

Use Synthetic Division to Determine Whether the Number K Is $\mathrm { k } = 1 ; \mathrm { f } ( \mathrm { x } ) = 5 \mathrm { x } ^ { 3 } + 7 \mathrm { x } ^ { 2 } + 4 \mathrm { x } + 6$