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Solve the Problem 78 m78 \mathrm {~m} If the Width Were Doubled and the Length Were

Question 65

Multiple Choice

Solve the problem.
-The perimeter of a rectangle is 78 m78 \mathrm {~m} . If the width were doubled and the length were increased by 16 m16 \mathrm {~m} , the perimeter would be 138 m138 \mathrm {~m} . What are the length and width of the rectangle?


A) width 19 m19 \mathrm {~m} , length 19 m19 \mathrm {~m}
B) width 14 m14 \mathrm {~m} , length 19 m19 \mathrm {~m}
C) width 25 m25 \mathrm {~m} , length 14 m14 \mathrm {~m}
D) width 14 m14 \mathrm {~m} , length 25 m25 \mathrm {~m}

Correct Answer:

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